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[Swift]LeetCode316. 去除重复字母 | Remove Duplicate Letters

时间:2019-01-12 18:52:46      阅读:29      评论:0      收藏:0      [点我收藏+]

标签:cab   rate   value   tel   ogr   enume   letter   Once   last   

Given a string which contains only lowercase letters, remove duplicate letters so that every letter appear once and only once. You must make sure your result is the smallest in lexicographical order among all possible results.

Example 1:

Input: "bcabc"
Output: "abc"

Example 2:

Input: "cbacdcbc"
Output: "acdb"

给定一个仅包含小写字母的字符串,去除字符串中重复的字母,使得每个字母只出现一次。需保证返回结果的字典序最小(要求不能打乱其他字符的相对位置)。

示例 1:

输入: "bcabc"
输出: "abc"

示例 2:

输入: "cbacdcbc"
输出: "acdb"

32ms
 1 class Solution {
 2     func removeDuplicateLetters(_ s: String) -> String {
 3         
 4         var counts = [Character: Int]()
 5         var used = [Character:Bool]()
 6         
 7         s.forEach {
 8             counts[$0, default: 0] += 1
 9         }
10         
11         var ans = [Character]()
12         
13         for ch in s {
14             counts[ch, default:0] -= 1
15             if used[ch, default: false] == true {
16                 continue
17             }                      
18             
19             while let last = ans.last, ch < last, counts[last]! > 0 {
20                 used[last] = false
21                 ans.removeLast()           
22             }
23             ans.append(ch)
24             used[ch] = true
25         }
26 
27         return String(ans)
28     }
29 }

36ms

  1 extension Character {
  2     var ascii: UInt32? {   
  3         guard let first = unicodeScalars.first else {
  4             return nil
  5         }
  6         return first.isASCII == true ? first.value : nil    
  7     }
  8 }
  9 
 10 class Solution {
 11     class IndexedTree {
 12         var n: Int
 13         var arr: [Int]
 14         
 15         init(_ n: Int) {
 16             self.n = n
 17             arr = [Int](repeating: 0, count: n+1)
 18         }
 19         
 20         func insert(_ index: Int) -> Void {
 21             var x = index
 22             while x <= n {
 23                 arr[x] += 1
 24                 x = x + x&(-x)
 25             }
 26         }
 27         
 28         func query(_ index: Int) -> Int {
 29             var x = index
 30             var sum = 0
 31             while x > 0 {
 32                 sum += arr[x]
 33                 x = x&(x-1)
 34             }
 35             return sum
 36         }
 37     }
 38     
 39 
 40     func transIndex(_ n: Int, _ index: Int) -> Int {
 41         return n-index
 42     }
 43     
 44     func removeDuplicateLetters(_ s: String) -> String {
 45         let charArr = Array(s)
 46         var ans = ""
 47         
 48         let n = charArr.count
 49         if n == 0 {
 50             return ans
 51         }
 52         
 53         var counts = [Int](repeating: 0, count: 26)
 54         var indice = [Int?](repeating: nil, count: 26)
 55         var used = [Bool](repeating: false, count: 26)
 56         
 57         let indexedTree = IndexedTree(charArr.count)
 58         let aAsc = "a".first!.ascii!
 59         
 60         for (i, ch) in charArr.enumerated(){
 61             let ci = Int(ch.ascii!-aAsc)
 62             counts[ci] += 1
 63         }
 64         
 65         var que = [Int]()
 66         for (i, ch) in charArr.enumerated() {
 67             let ci = Int(ch.ascii!-aAsc)
 68             if counts[ci] == 0 {
 69                 continue
 70             }
 71 
 72 
 73             
 74             if indice[ci] == nil {
 75                 while let last = que.last {
 76                     if last > ci {
 77                         que.removeLast()
 78                         indice[last] = nil
 79                     } else {
 80                         break
 81                     }
 82                 }
 83                 
 84                 indice[ci] = i
 85                 que.append(ci)
 86             }
 87             
 88             counts[ci] -= 1
 89             if counts[ci] == 0 {
 90                 while let ii = que.first, ii <= ci {
 91                     let index = indice[ii]!
 92                     ans += String(charArr[index])
 93                     indice[ii] = nil
 94                     counts[ii] = 0
 95                     que.removeFirst()
 96                 }
 97             }
 98 
 99         }
100     
101         return ans
102     }
103 }

52ms

 1 class Solution {
 2     func removeDuplicateLetters(_ s: String) -> String {
 3         let sArr = Array(s)
 4         
 5         var counts = [Character : Int]()
 6         
 7         for c in sArr {
 8             if counts[c] == nil {
 9                 counts[c] = 1
10             }else {
11                 counts[c]! += 1
12             }
13         }
14         
15         var res = [Character]()
16         
17         for c in sArr {
18             if !res.contains(c) {
19                 while !res.isEmpty && counts[res.last!] != 0 && res.last! > c  {
20                     res.removeLast()
21                 }
22                 res.append(c)
23                 
24             }
25             counts[c]! -= 1
26         }
27         
28         return String(res)
29     }
30 }

 

[Swift]LeetCode316. 去除重复字母 | Remove Duplicate Letters

标签:cab   rate   value   tel   ogr   enume   letter   Once   last   

原文:https://www.cnblogs.com/strengthen/p/10260578.html

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